what are the oxidation numbers of the atoms in this reaction? check all that apply. ch4(g) + 2o2(g) → co2(g)…

what are the oxidation numbers of the atoms in this reaction? check all that apply. ch4(g) + 2o2(g) → co2(g) + 2h2o(g) -4 for c in ch4 +4 for c in co2 -2 for o in all substances +1 for h in both ch4 and h2o +4 for o in h2o done

what are the oxidation numbers of the atoms in this reaction? check all that apply. ch4(g) + 2o2(g) → co2(g) + 2h2o(g) -4 for c in ch4 +4 for c in co2 -2 for o in all substances +1 for h in both ch4 and h2o +4 for o in h2o done

Answer

Explanation:

Step1: Determine C in CH₄

Hydrogen has an oxidation number of +1 in most compounds. In CH₄, let the oxidation number of C be (x). Since there are 4 H atoms and the molecule is neutral, (x + 4\times(+1)=0), so (x=- 4).

Step2: Determine C in CO₂

Oxygen has an oxidation - number of - 2 in most compounds. In CO₂, let the oxidation number of C be (y). Since there are 2 O atoms and the molecule is neutral, (y+2\times(-2) = 0), so (y = +4).

Step3: Determine O oxidation number

Oxygen usually has an oxidation number of - 2 in compounds (except in peroxides and elemental oxygen). In O₂, it is 0, but in CO₂ and H₂O, it is - 2.

Step4: Determine H oxidation number

Hydrogen has an oxidation number of +1 in most compounds. In CH₄ and H₂O, it is +1.

Answer:

-4 for C in CH₄, +4 for C in CO₂, -2 for O in all substances (except O₂), +1 for H in both CH₄ and H₂O