what are the oxidation numbers of the atoms in this reaction? check all that apply. mg(s) + 2hcl(aq) →…

what are the oxidation numbers of the atoms in this reaction? check all that apply. mg(s) + 2hcl(aq) → mgcl₂(aq) + h₂(g) 0 for mg in mg and mgcl₂ 0 for mg(s) and h in h₂ +1 for h in hcl -1 for cl in hcl +2 for mg in mgcl₂ done

what are the oxidation numbers of the atoms in this reaction? check all that apply. mg(s) + 2hcl(aq) → mgcl₂(aq) + h₂(g) 0 for mg in mg and mgcl₂ 0 for mg(s) and h in h₂ +1 for h in hcl -1 for cl in hcl +2 for mg in mgcl₂ done

Answer

Explanation:

Step1: Oxidation number of elements in free - state

Elements in their free state have an oxidation number of 0. Mg(s) is in its free state, so the oxidation number of Mg in Mg(s) is 0. H₂(g) is also in its free state, so the oxidation number of H in H₂ is 0.

Step2: Oxidation number in HCl

In HCl, Cl is more electronegative than H. The oxidation number of Cl in binary compounds with non - metals is usually - 1. Let the oxidation number of H be x. For HCl, x+( - 1)=0, so x = + 1.

Step3: Oxidation number in MgCl₂

In MgCl₂, the oxidation number of Cl is - 1. Let the oxidation number of Mg be y. Since there are 2 Cl atoms and the overall charge of the compound is 0, we have y + 2×( - 1)=0, so y=+2.

Answer:

  • 0 for Mg(s) and H in H₂
  • +1 for H in HCl
  • -1 for Cl in HCl
  • +2 for Mg in MgCl₂