part 3: independent work\ntry balancing these more complex equations. show your work:\n1. c3h8+o2→co2+h2o\nwo…

Explanation:

Step1: Balance carbon atoms for C3H8+O2→CO2+H2O

There are 3 carbon atoms in C3H8. So, we put a 3 in front of CO2: C3H8+O2→3CO2+H2O

Step2: Balance hydrogen atoms

There are 8 hydrogen atoms in C3H8. So, we put a 4 in front of H2O: C3H8+O2→3CO2 + 4H2O

Step3: Balance oxygen atoms

On the right - hand side, there are 3×2 + 4×1=10 oxygen atoms. So, we put a 5 in front of O2. The balanced equation is C3H8+5O2→3CO2+4H2O

Step4: Balance oxygen atoms for KClO3→KCl+O2

Let's start by balancing the oxygen atoms. The least - common multiple of 2 and 3 (the number of oxygen atoms in O2 and KClO3 respectively) is 6. So, we put a 2 in front of KClO3 and a 3 in front of O2: 2KClO3→KCl+3O2

Step5: Balance potassium and chlorine atoms

Now, we have 2 potassium and 2 chlorine atoms on the left - hand side. So, we put a 2 in front of KCl. The balanced equation is 2KClO3→2KCl+3O2

Step6: Balance calcium atoms for Ca(OH)2+H3PO4→Ca3(PO4)2+H2O

There are 3 calcium atoms in Ca3(PO4)2. So, we put a 3 in front of Ca(OH)2: 3Ca(OH)2+H3PO4→Ca3(PO4)2+H2O

Step7: Balance phosphate groups

There are 2 phosphate groups in Ca3(PO4)2. So, we put a 2 in front of H3PO4: 3Ca(OH)2+2H3PO4→Ca3(PO4)2+H2O

Step8: Balance hydrogen and oxygen atoms

On the left - hand side, there are 3×2 + 2×3 = 12 hydrogen atoms and 3×2+2×4 = 14 oxygen atoms. On the right - hand side, in Ca3(PO4)2 there are 8 oxygen atoms. So, we put a 6 in front of H2O. The balanced equation is 3Ca(OH)2+2H3PO4→Ca3(PO4)2+6H2O

Answer:

1. C3H8+5O2→3CO2+4H2O
2. 2KClO3→2KCl+3O2
3. 3Ca(OH)2+2H3PO4→Ca3(PO4)2+6H2O