part of one row of the periodic table is shown. which elements atoms have the greatest average number of…

part of one row of the periodic table is shown. which elements atoms have the greatest average number of neutrons? 50 sn tin 118.71 51 sb antimony 121.76 52 te tellurium 127.60 53 i iodine 126.90 〇 tin (sn) 〇 antimony (sb) 〇 tellurium (te) 〇 iodine (i)

part of one row of the periodic table is shown. which elements atoms have the greatest average number of neutrons? 50 sn tin 118.71 51 sb antimony 121.76 52 te tellurium 127.60 53 i iodine 126.90 〇 tin (sn) 〇 antimony (sb) 〇 tellurium (te) 〇 iodine (i)

Answer

Explanation:

Step1: Recall atomic number and average atomic mass relationship

The average number of neutrons = average atomic mass - atomic number.

Step2: Calculate neutrons for tin (Sn)

Atomic number of Sn is 50, average atomic mass is 118.71. So number of neutrons = $118.71 - 50=68.71$.

Step3: Calculate neutrons for antimony (Sb)

Atomic number of Sb is 51, average atomic mass is 121.76. So number of neutrons = $121.76 - 51 = 70.76$.

Step4: Calculate neutrons for tellurium (Te)

Atomic number of Te is 52, average atomic mass is 127.60. So number of neutrons = $127.60 - 52=75.60$.

Step5: Calculate neutrons for iodine (I)

Atomic number of I is 53, average atomic mass is 126.90. So number of neutrons = $126.90 - 53 = 73.90$.

Answer:

tellurium (Te)