part a the students data can be seen here. a chemical reaction clearly took place in the flask. one entry is…

part a the students data can be seen here. a chemical reaction clearly took place in the flask. one entry is missing: the mass of the system at the end of the experiment. what amount should be added to the data table? a 485.68g b less than 485.68g c more than 485.68g d cannot be determined part b ms. soseman, the science teacher wrote a partial equation for the reaction on the whiteboard. fe + o₂ → fe₂o₃ using the law of conservation of mass as your guide, balance this chemical equation. a 2fe + 3o₂ → fe₂o₃ b 2fe + o₂ → fe₂o₃ c 4fe + 3o₂ → 2fe₂o₃

part a the students data can be seen here. a chemical reaction clearly took place in the flask. one entry is missing: the mass of the system at the end of the experiment. what amount should be added to the data table? a 485.68g b less than 485.68g c more than 485.68g d cannot be determined part b ms. soseman, the science teacher wrote a partial equation for the reaction on the whiteboard. fe + o₂ → fe₂o₃ using the law of conservation of mass as your guide, balance this chemical equation. a 2fe + 3o₂ → fe₂o₃ b 2fe + o₂ → fe₂o₃ c 4fe + 3o₂ → 2fe₂o₃

Answer

Explanation:

Step1: Recall law of conservation of mass

In a closed - system chemical reaction, mass is conserved. Without information about whether the system is open or closed and what products are formed (if any gas is released etc.), we cannot determine the final mass.

Step2: Analyze Part B

For balancing the chemical equation $Fe + O_2\rightarrow Fe_2O_3$, we need to have an equal number of atoms of each element on both sides. For iron (Fe), on the right - hand side, there are 2 Fe atoms in $Fe_2O_3$. On the left - hand side, we start with 1 Fe atom. For oxygen (O), on the right - hand side, there are 3 O atoms in $Fe_2O_3$, and on the left - hand side, we have 2 O atoms in $O_2$. By trial and error or a systematic approach, we find that $4Fe+3O_2\rightarrow 2Fe_2O_3$ balances the equation as we have 4 Fe atoms and 6 O atoms on both sides.

Answer:

Part A: D. cannot be determined Part B: C. $4Fe + 3O_2\rightarrow 2Fe_2O_3$