part 1: unit quiz 2a - electronic structure\ncomplete the table below by filling in the missing information…

part 1: unit quiz 2a - electronic structure\ncomplete the table below by filling in the missing information. all elements in the table are neutral.\ngive the full electron configuration for elements with less than 18 electrons.\ngive the noble gas electron configuration for elements with more than 18 electrons.\n| element symbol | total number of electrons | electron configuration | number of valence electrons | lewis dot structure |\n| ---- | ---- | ---- | ---- | ---- |\n| al | | | | |\n| | | 1s²2s²2p⁶3s²3p³ | | |\n| | | | | •as• |
Answer
Explanation:
Step1: Determine total electrons for Al
Al (aluminum) has an atomic number of 13. So the total number of electrons in a neutral Al atom is 13.
Step2: Write electron - configuration for Al
The electron - configuration of Al is (1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}).
Step3: Find number of valence electrons for Al
The electrons in the outermost shell are valence electrons. For Al, the outermost shell is the 3rd shell ((3s^{2}3p^{1})), so the number of valence electrons is 3.
Step4: Analyze the given electron - configuration (1s^{2}2s^{2}2p^{6}3s^{2}3p^{3})
The sum of the electrons in this configuration is (2 + 2+6 + 2+3=15). The element with 15 electrons is P (phosphorus). The number of valence electrons for P is 5 (from (3s^{2}3p^{3})).
Step5: Analyze the Lewis - dot structure (\cdot\text{As}\cdot)
As (arsenic) has an atomic number of 33. The number of valence electrons for As is 5. The total number of electrons in As is 33. The noble - gas electron - configuration for As is ([Ar]4s^{2}3d^{10}4p^{3}).
Answer:
| ELEMENT SYMBOL | TOTAL NUMBER OF ELECTRONS | ELECTRON CONFIGURATION | NUMBER OF VALENCE ELECTRONS | LEWIS DOT STRUCTURE |
|---|---|---|---|---|
| Al | 13 | (1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}) | 3 | (\cdot\text{Al}\cdot) |
| P | 15 | (1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}) | 5 | (\cdot\text{P}\cdot) |
| As | 33 | ([Ar]4s^{2}3d^{10}4p^{3}) | 5 | (\cdot\text{As}\cdot) |