passing an electric current through a sample of water (h₂o) can cause the water to decompose into hydrogen…

passing an electric current through a sample of water (h₂o) can cause the water to decompose into hydrogen gas (h₂) and oxygen gas (o₂) according to the following equation.\n2h₂o → 2h₂ + o₂\nthe molar mass of h₂o is 18.02 g/mol. the molar mass of o₂ is 32.00 g/mol. what mass of h₂o, in grams, must react to produce 50.00 g of o₂?\no 14.08 grams\no 28.16 grams\no 44.40 grams\no 56.31 grams

passing an electric current through a sample of water (h₂o) can cause the water to decompose into hydrogen gas (h₂) and oxygen gas (o₂) according to the following equation.\n2h₂o → 2h₂ + o₂\nthe molar mass of h₂o is 18.02 g/mol. the molar mass of o₂ is 32.00 g/mol. what mass of h₂o, in grams, must react to produce 50.00 g of o₂?\no 14.08 grams\no 28.16 grams\no 44.40 grams\no 56.31 grams

Answer

Explanation:

Step1: Calculate moles of O₂

Use the formula $n=\frac{m}{M}$, where $n$ is the number of moles, $m$ is the mass, and $M$ is the molar - mass. Given $m_{O_2}=50.00\ g$ and $M_{O_2}=32.00\ g/mol$. $n_{O_2}=\frac{50.00\ g}{32.00\ g/mol}=\frac{50}{32}\ mol$

Step2: Determine moles of H₂O from the mole - ratio

From the balanced chemical equation $2H_2O\rightarrow2H_2 + O_2$, the mole - ratio of $H_2O$ to $O_2$ is $2:1$. So, $n_{H_2O}=2\times n_{O_2}$. $n_{H_2O}=2\times\frac{50}{32}\ mol=\frac{100}{32}\ mol$

Step3: Calculate mass of H₂O

Use the formula $m = n\times M$. Given $n_{H_2O}=\frac{100}{32}\ mol$ and $M_{H_2O}=18.02\ g/mol$. $m_{H_2O}=\frac{100}{32}\ mol\times18.02\ g/mol=\frac{1802}{32}\ g = 56.3125\ g\approx56.31\ g$

Answer:

56.31 grams