what is the percent by mass of potassium in k₃fe(cn)₆? use %element = \\frac{total mass of element in…

what is the percent by mass of potassium in k₃fe(cn)₆? use %element = \\frac{total mass of element in compound}{molar mass of compound}×100. 16.96% 21.88% 25.53% 35.62%

what is the percent by mass of potassium in k₃fe(cn)₆? use %element = \\frac{total mass of element in compound}{molar mass of compound}×100. 16.96% 21.88% 25.53% 35.62%

Answer

Answer:

D. 35.62%

Explanation:

Step1: Calculate molar mass of K

The molar mass of potassium (K) is approximately 39.098 g/mol. In (K_3Fe(CN)_6), there are 3 K atoms. So the total mass of K in the compound is (3\times39.098 = 117.294) g/mol.

Step2: Calculate molar mass of (K_3Fe(CN)_6)

The molar mass of Fe is approximately 55.845 g/mol, C is approximately 12.011 g/mol, and N is approximately 14.007 g/mol. The molar mass of (K_3Fe(CN)_6=3\times39.098 + 55.845+6\times(12.011 + 14.007)) (=117.294+55.845 + 6\times26.018) (=117.294+55.845+156.108) (=329.247) g/mol.

Step3: Calculate mass - percent of K

Using the formula (%\text{Element}=\frac{\text{total mass of element in compound}}{\text{molar mass of compound}}\times100), we substitute the values: (%\text{K}=\frac{117.294}{329.247}\times 100\approx35.62%)