what is the ph of a solution with h⁺ = 1.25 × 10⁻¹⁰ m? use ph = -logh₃o⁺.\n-10.1\n-9.90\n7.90\n9.90
what is the ph of a solution with h⁺ = 1.25 × 10⁻¹⁰ m? use ph = -logh₃o⁺.\n-10.1\n-9.90\n7.90\n9.90
Answer
Explanation:
Step1: Substitute the value of [H⁺] into pH formula
Given $[H^+]=1.25\times 10^{-10}\ M$ and $pH =-\log[H^+]$, so $pH=-\log(1.25\times 10^{-10})$.
Step2: Use logarithm property
According to the logarithm property $\log(ab)=\log a+\log b$, we have $pH=-(\log(1.25)+\log(10^{-10}))$. Since $\log(10^{-10})=- 10$ and $\log(1.25)\approx0.1$, then $pH=- (0.1 - 10)$.
Step3: Calculate the pH value
$pH=-0.1 + 10=9.90$.
Answer:
D. 9.90