what is the ph of a solution of h₂so₄ that has h₃o⁺=5.45×10⁻⁵ m? round to the nearest hundredth.

Answer:

4.26

Explanation:

Step1: Recall pH formula

$pH = -\log[H_3O^+]$

Step2: Substitute the given value

$pH=-\log(5.45\times 10^{-5})$

Step3: Calculate the result

Using a calculator, $-\log(5.45\times 10^{-5})\approx4.26$