the ph of a solution is a measure of the quantity of hydrogen atoms (h) in the solution. it is given by the…

the ph of a solution is a measure of the quantity of hydrogen atoms (h) in the solution. it is given by the formula f(x)= -log x. in the formula, x = h+, the molar concentration of hydrogen atoms, or the number of moles of hydrogen atoms per liter of solution. the approximate molar concentration of several chemicals are given. find the ph of each. use the calculator and round to the nearest tenth, if necessary. oven cleaner: h+=10^(-13) ph = water: h+=0.0000007 ph = blood: h+=0.00000004 ph = vinegar: h+=0.0063 ph =
Answer
Explanation:
Step1: Recall pH formula
$pH = -\log[x]$, where $x = [H^+]$.
Step2: Calculate pH of oven - cleaner
For oven - cleaner, $x = 10^{-13}$. Then $pH=-\log(10^{-13})$. Since $\log(10^{-13})=- 13$, so $pH = 13$.
Step3: Calculate pH of water
For water, $x = 0.0000007=7\times10^{-7}$. Then $pH = -\log(7\times10^{-7})=-\left(\log7+\log(10^{-7})\right)$. $\log7\approx0.845$ and $\log(10^{-7})=-7$. So $pH\approx-(0.845 - 7)=6.2$.
Step4: Calculate pH of blood
For blood, $x = 0.00000004 = 4\times10^{-8}$. Then $pH=-\log(4\times10^{-8})=-\left(\log4+\log(10^{-8})\right)$. $\log4\approx0.602$ and $\log(10^{-8})=-8$. So $pH\approx-(0.602 - 8)=7.4$.
Step5: Calculate pH of vinegar
For vinegar, $x = 0.0063 = 6.3\times10^{-3}$. Then $pH=-\log(6.3\times10^{-3})=-\left(\log6.3+\log(10^{-3})\right)$. $\log6.3\approx0.800$ and $\log(10^{-3})=-3$. So $pH\approx-(0.800 - 3)=2.2$.
Answer:
Oven cleaner: $13$ Water: $6.2$ Blood: $7.4$ Vinegar: $2.2$