what is the ph of a solution that has the same number of hydrogen ions as hydroxide ions?\n0\n1\n7\n14

Explanation:

Step1: Recall pH - pOH relationship

The relationship between pH and pOH is given by pH + pOH=14. In a neutral solution, the concentration of hydrogen ions $[H^+]$ is equal to the concentration of hydroxide ions $[OH^-]$.

Step2: Determine pOH for neutral solution

Since $[H^+]=[OH^-]$, and $K_w = [H^+][OH^-]=1.0\times10^{- 14}$. When $[H^+]=[OH^-]$, then $[H^+]=[OH^-]=1.0\times10^{-7}\ M$. The pOH is calculated as $pOH=-\log[OH^-]$. Substituting $[OH^-]=1.0\times10^{-7}\ M$ into the pOH formula, we get $pOH = 7$.

Step3: Calculate pH

Using the formula pH + pOH = 14, and since pOH = 7, then pH=14 - pOH. Substituting pOH = 7 into the formula, we get pH = 7.

Answer:

7