place the coefficients into the underlined spaces to balance the chemical equation. not all coefficients…

place the coefficients into the underlined spaces to balance the chemical equation. not all coefficients must be used and some may be used more than once. _ c3h8(g)+ _ o2(g)→ _ co2(g) + _ h2o(l) 1 2 3 4 5

place the coefficients into the underlined spaces to balance the chemical equation. not all coefficients must be used and some may be used more than once. _ c3h8(g)+ _ o2(g)→ _ co2(g) + _ h2o(l) 1 2 3 4 5

Answer

Explanation:

Step1: Balance carbon atoms

There are 3 carbon atoms in $C_3H_8$. So, the coefficient of $CO_2$ should be 3 to balance carbon atoms. The equation becomes $C_3H_8(g)+ \underline{ }O_2(g)\longrightarrow3CO_2(g)+\underline{ }H_2O(l)$.

Step2: Balance hydrogen atoms

There are 8 hydrogen atoms in $C_3H_8$. Since each $H_2O$ molecule has 2 hydrogen - atoms, the coefficient of $H_2O$ should be 4 to balance hydrogen atoms. The equation is now $C_3H_8(g)+ \underline{ }O_2(g)\longrightarrow3CO_2(g)+4H_2O(l)$.

Step3: Balance oxygen atoms

On the right - hand side, there are $3\times2 + 4\times1=10$ oxygen atoms in $3CO_2$ and $4H_2O$. So, the coefficient of $O_2$ should be 5 to balance oxygen atoms. The balanced equation is $C_3H_8(g)+5O_2(g)\longrightarrow3CO_2(g)+4H_2O(l)$.

Answer:

1, 5, 3, 4