place the coefficients into the underlined spaces to balance the chemical equation. not all coefficients…

place the coefficients into the underlined spaces to balance the chemical equation. not all coefficients must be used and some may be used more than once.\n_ c₃h₈(g)+ _ o₂(g)→ _ co₂(g) + _ h₂o(l)\n1 2 3 4 5

place the coefficients into the underlined spaces to balance the chemical equation. not all coefficients must be used and some may be used more than once.\n_ c₃h₈(g)+ _ o₂(g)→ _ co₂(g) + _ h₂o(l)\n1 2 3 4 5

Answer

Explanation:

Step1: Balance carbon atoms

There are 3 carbon atoms in $C_3H_8$. So, to balance carbon in $CO_2$, the coefficient of $CO_2$ should be 3. $C_3H_8(g)+ \underline{?}O_2(g)\rightarrow 3CO_2(g)+\underline{?}H_2O(l)$

Step2: Balance hydrogen atoms

There are 8 hydrogen atoms in $C_3H_8$. Since each $H_2O$ molecule has 2 hydrogen atoms, the coefficient of $H_2O$ should be 4 to balance hydrogen. $C_3H_8(g)+ \underline{?}O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)$

Step3: Balance oxygen atoms

On the right - hand side, there are $3\times2 + 4\times1=10$ oxygen atoms in $3CO_2$ and $4H_2O$. So, the coefficient of $O_2$ should be 5 to balance oxygen on the left - hand side. $C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)$

Answer:

1, 5, 3, 4