place the following atoms in order of increasing atomic radius (1 = smallest, 4 = largest): n, p, sb, bi.

place the following atoms in order of increasing atomic radius (1 = smallest, 4 = largest): n, p, sb, bi.
Answer
Explanation:
Step1: Recall atomic - radius trend
Atomic radius increases down a group and decreases across a period. N, P, Sb, and Bi are all in Group 15.
Step2: Identify period number
N is in Period 2, P is in Period 3, Sb is in Period 5, and Bi is in Period 6.
Step3: Order by atomic radius
As we go down the group, the atomic radius increases. So the order of increasing atomic radius is N < P < Sb < Bi.
Answer:
N = 1, P = 2, Sb = 3, Bi = 4