the poh of a 0.0200 m solution of hcl is

Explanation:

Step1: Determine $H^+$ concentration

HCl is a strong - acid, so $[H^+]=0.0200\ M$.

Step2: Calculate pH

$pH =-\log[H^+]=-\log(0.0200)=1.70$.

Step3: Calculate pOH

We know that $pH + pOH=14$. So $pOH = 14 - pH$. Substituting the value of pH, we get $pOH=14 - 1.70 = 12.30$.

Answer:

12.30