the poh of a 0.300 m solution of naoh is

Explanation:

Step1: Identify $[OH^-]$ concentration

NaOH is a strong - base and dissociates completely as $NaOH\rightarrow Na^+ + OH^-$. So, if $[NaOH]=0.300\ M$, then $[OH^-]=0.300\ M$.

Step2: Use pOH formula

The formula for pOH is $pOH =-\log[OH^-]$. Substitute $[OH^-]=0.300$ into the formula: $pOH=-\log(0.300)$.

Step3: Calculate the value

$pOH = 0.523$

Answer:

$0.523$