potassium chromate\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this…

potassium chromate\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this question.\npart d\ncopper(i) fluoride\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this question.

potassium chromate\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this question.\npart d\ncopper(i) fluoride\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this question.

Answer

Explanation:

Step1: Determine ions in potassium chromate

Potassium has a +1 charge ($K^+$) and chromate ion ($CrO_4^{2 - }$) has a - 2 charge.

Step2: Balance charges

To balance the charges, we need 2 potassium ions for 1 chromate ion.

Step3: Write chemical formula for potassium chromate

$K_2CrO_4$

Step4: Determine ions in copper(I) fluoride

Copper(I) has a +1 charge ($Cu^+$) and fluoride ion ($F^-$) has a - 1 charge.

Step5: Write chemical formula for copper(I) fluoride

Since the charges are equal in magnitude and opposite in sign, the chemical formula is $CuF$.

Answer:

Potassium chromate: $K_2CrO_4$ Copper(I) fluoride: $CuF$