practice: balancing equations #1\nshow all work on a separate sheet of paper. place coefficients (not…

Explanation:

Step1: Balance equation 6

For $C + S_2\rightarrow CS_2$, the number of atoms of each element is already the same on both sides. So the coefficients are 1, 1, 1.

Step2: Balance equation 7

For $Na+O_2\rightarrow Na_2O_2$, to balance sodium and oxygen, we need 2 Na on the left - hand side. So the coefficients are 2, 1, 1.

Step3: Balance equation 8

For $N_2 + O_2\rightarrow N_2O_5$, we need 5 oxygen atoms on the right - hand side. Multiply $O_2$ by $\frac{5}{2}$ and $N_2O_5$ by 1, $N_2$ by 1. To get whole - number coefficients, multiply all by 2. So the coefficients are 2, 5, 2.

Step4: Balance equation 9

For $H_3PO_4+Mg(OH)_2\rightarrow Mg_3(PO_4)_2 + H_2O$, balance magnesium first. We need 3 $Mg(OH)_2$. Then balance phosphorus, which is already balanced. For hydrogen and oxygen, we need 2 $H_3PO_4$ and 6 $H_2O$. So the coefficients are 2, 3, 1, 6.

Step5: Balance equation 10

For $NaOH + H_2CO_3\rightarrow Na_2CO_3+H_2O$, balance sodium first. We need 2 $NaOH$. Then the equation is balanced. So the coefficients are 2, 1, 1, 1.

Step6: Balance equation 11

For $KOH + HBr\rightarrow KBr + H_2O$, the equation is already balanced with coefficients 1, 1, 1, 1.

Step7: Balance equation 12

For $H_2+O_2\rightarrow H_2O_2$, the equation is balanced with coefficients 1, 1, 1.

Step8: Balance equation 13

For $Na + O_2\rightarrow Na_2O$, we need 4 Na on the left - hand side to balance sodium and oxygen. So the coefficients are 4, 1, 2.

Step9: Balance equation 14

For $Al(OH)_3+H_2CO_3\rightarrow Al_2(CO_3)_3 + H_2O$, balance aluminum first. We need 2 $Al(OH)_3$. Then balance carbonate and hydrogen - oxygen. We need 3 $H_2CO_3$ and 6 $H_2O$. So the coefficients are 2, 3, 1, 6.

Step10: Balance equation 15

For $Al+S_8\rightarrow Al_2S_3$, balance sulfur first. We need 8 $Al_2S_3$ and 3 $S_8$. Then balance aluminum, we need 16 $Al$. So the coefficients are 16, 3, 8.

Step11: Balance equation 16

For $Ca + N_2\rightarrow Ca_3N_2$, we need 3 Ca on the left - hand side. So the coefficients are 3, 1, 1.

Step12: Balance equation 17

For $Mg+Cl_2\rightarrow MgCl_2$, the equation is balanced with coefficients 1, 1, 1.

Step13: Balance equation 18

For $Rb+RbNO_3\rightarrow Rb_2O + N_2$, balance nitrogen first. We need 2 $RbNO_3$. Then balance oxygen and rubidium. We need 10 $Rb$, 2 $RbNO_3$, 5 $Rb_2O$ and 1 $N_2$. So the coefficients are 10, 2, 5, 1.

Step14: Balance equation 19

For $C_6H_6+O_2\rightarrow CO_2 + H_2O$, balance carbon first. We need 6 $CO_2$. Then balance hydrogen, we need 3 $H_2O$. Then balance oxygen, we need $\frac{15}{2}O_2$. Multiply all by 2 to get whole - number coefficients. So the coefficients are 2, 15, 12, 6.

Step15: Balance equation 20

For $N_2+H_2\rightarrow NH_3$, we need 2 $NH_3$ to balance nitrogen and 3 $H_2$ to balance hydrogen. So the coefficients are 1, 3, 2.

Answer:

6. 1, 1, 1
7. 2, 1, 1
8. 2, 5, 2
9. 2, 3, 1, 6
10. 2, 1, 1, 1
11. 1, 1, 1, 1
12. 1, 1, 1
13. 4, 1, 2
14. 2, 3, 1, 6
15. 16, 3, 8
16. 3, 1, 1
17. 1, 1, 1
18. 10, 2, 5, 1
19. 2, 15, 12, 6
20. 1, 3, 2