3. what pressure is required to compress 196.0 liters of air at 1.00 atm into a cylinder whose volume is…

Explanation:

Step1: Identify the formula

Boyle's Law: (P_1V_1 = P_2V_2), where (P_1) is the initial pressure, (V_1) is the initial volume, (P_2) is the final pressure, and (V_2) is the final volume.

Step2: Rearrange the formula to solve for (P_2)

(P_2=\frac{P_1V_1}{V_2})

Step3: Substitute the given values

Given (P_1 = 1.00\space atm), (V_1=196.0\space L), (V_2 = 26.0\space L) (P_2=\frac{1.00\space atm\times196.0\space L}{26.0\space L})

Step4: Calculate (P_2)

(P_2=\frac{196.0}{26.0}\space atm\approx 7.54\space atm)

Answer:

(7.54\space atm)