problem #2: a scientist produces 8.00 moles o...
problem #2: a scientist produces 8.00 moles of water (h2o) using the equation below. how many grams of oxygen (o2) were needed? ch4 + 2o2 → co2 + 2h2o 8.00 moles h2o? grams o2 16.0 grams oxygen 64.0 grams oxygen 128 grams oxygen 256 grams oxygen
Answer
# Explanation:
## Step1: Determine the mole ratio of \(O_2\) to \(H_2O\)
From the balanced chemical equation \(CH_4 + 2O_2\rightarrow CO_2 + 2H_2O\), the mole ratio of \(O_2\) to \(H_2O\) is \(2:2 = 1:1\).
## Step2: Calculate the moles of \(O_2\)
Given \(n(H_2O)=8.00\) moles. Since the mole ratio \(n(O_2):n(H_2O) = 1:1\), then \(n(O_2)=8.00\) moles.
## Step3: Calculate the molar mass of \(O_2\)
The molar mass of \(O\) is \(16.0\) g/mol. For \(O_2\), \(M = 2\times16.0=32.0\) g/mol.
## Step4: Calculate the mass of \(O_2\)
Using the formula \(m = n\times M\), where \(n = 8.00\) moles and \(M = 32.0\) g/mol. Then \(m=8.00\times32.0 = 256\) grams.
# Answer:
256 grams oxygen