what is produced during the replacement reaction of ba(no₃)₂ and na₂so₄?\no 2bana + 2no₃so₄\no 2nano₃ +…

Explanation:

Step1: Write the reaction equation

A double - replacement reaction of $Ba(NO_3)_2$ and $Na_2SO_4$ has the general form of $AB + CD\rightarrow AD+CB$. Here, $A = Ba^{2 + }$, $B=NO_3^{-}$, $C = Na^{+}$, $D = SO_4^{2 - }$. The reaction is $Ba(NO_3)_2+Na_2SO_4\rightarrow BaSO_4 + 2NaNO_3$.

Step2: Balance the equation

On the left - hand side, we have 1 Ba, 2 $NO_3^{-}$, 2 Na, and 1 $SO_4^{2 - }$. On the right - hand side, in $BaSO_4$ we have 1 Ba and 1 $SO_4^{2 - }$, and in $NaNO_3$ we have 1 Na and 1 $NO_3^{-}$. To balance the sodium and nitrate ions, we need 2 moles of $NaNO_3$.

Answer:

2NaNO₃ + BaSO₄