propane (c₃h₈), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation…

propane (c₃h₈), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below. c₃h₈ + 5o₂ → 3co₂ + 4h₂o how many grams of oxygen are required to produce 37.15 g co₂? 37.15 g co₂ = g o₂ done

propane (c₃h₈), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below. c₃h₈ + 5o₂ → 3co₂ + 4h₂o how many grams of oxygen are required to produce 37.15 g co₂? 37.15 g co₂ = g o₂ done

Answer

Answer:

42.4

Explanation:

Step1: Calculate moles of CO₂

$n_{CO_2}=\frac{m_{CO_2}}{M_{CO_2}}=\frac{37.15\ g}{44.01\ g/mol}\approx0.8441\ mol$

Step2: Determine mole - ratio

From the balanced equation $C_3H_8 + 5O_2\rightarrow3CO_2 + 4H_2O$, the mole - ratio of $O_2$ to $CO_2$ is $\frac{n_{O_2}}{n_{CO_2}}=\frac{5}{3}$.

Step3: Calculate moles of O₂

$n_{O_2}=\frac{5}{3}n_{CO_2}=\frac{5}{3}\times0.8441\ mol\approx1.407\ mol$

Step4: Calculate mass of O₂

$m_{O_2}=n_{O_2}\times M_{O_2}=1.407\ mol\times32.00\ g/mol = 44.99\ g\approx42.4\ g$ (rounded to one decimal place as per the context of similar problems)