properties of two elements\nproperty beryllium sodium\nfamily alkaline earth metal alkali metal\ncolor…

properties of two elements\nproperty beryllium sodium\nfamily alkaline earth metal alkali metal\ncolor silvery gray/white\nreactivity high very high\ncompound formed with nitrogen be₃n₂ na₃n\nscientists are studying an unknown element and temporarily call it x. the unknown element x is white and is highly reactive. to figure out which family the unknown element belongs to, the scientists react x with nitrogen (n) ions and analyze the ionic compound that forms.\nselect words from the lists to complete the sentence.\nbased on the tables shown, the unknown element is most likely an metal with a chemical formula that has x ions and n ion(s).
Answer
Explanation:
Step1: Analyze element properties
The unknown element X is white and highly reactive. Sodium (an alkali - metal) is gray/white and very reactive. So X is likely an alkali metal.
Step2: Determine ion ratio in compound
Nitrogen forms $N^{3 - }$ ions. Alkali metals form $M^{+}$ ions (where M is the alkali - metal). To form a neutral compound, for every $N^{3 - }$ ion, we need 3 alkali - metal ions. So the compound will have 3 X ions and 1 N ion.
Answer:
Alkali; 3; 1