of protons, neutrons and electrons in the following: (4 pts)\n52\nte\ntellurium\n127.60\np⁺____ n°____ e⁻____
of protons, neutrons and electrons in the following: (4 pts)\n52\nte\ntellurium\n127.60\np⁺____ n°____ e⁻____
Answer
Explanation:
Step1: Determine number of protons
Atomic number = number of protons. For Te (Tellurium), atomic number is 52, so $p^{+}=52$.
Step2: Determine number of electrons
In a neutral atom, number of electrons = number of protons. So $e^{-}=52$.
Step3: Determine number of neutrons
Mass number (average atomic mass rounded) - atomic number = number of neutrons. Rounding 127.60 to 128, $n^{0}=128 - 52=76$.
Answer:
$p^{+}=52$, $n^{0}=76$, $e^{-}=52$