q1 chemistry: u2l12 electron config day 2\nprepwork part 1:\nfollow the exemplar answer below and write the…

Explanation:

Step1: Determine electrons of Lithium

Lithium has atomic number 3, so 3 electrons. $1s^{2}2s^{1}$

Step2: Draw orbital diagram for Lithium

$\frac{1\downarrow}{1s}\frac{1}{2s}$

Step3: Determine electrons of Aluminum

Aluminum has atomic number 13, so 13 electrons. $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$

Step4: Draw orbital diagram for Aluminum

$\frac{1\downarrow}{1s}\frac{1\downarrow}{2s}\frac{1\downarrow1\downarrow1\downarrow}{2p}\frac{1\downarrow}{3s}\frac{1}{3p}$

Step5: Determine electrons of Magnesium

Magnesium has atomic number 12, so 12 electrons. $1s^{2}2s^{2}2p^{6}3s^{2}$

Step6: Draw orbital diagram for Magnesium

$\frac{1\downarrow}{1s}\frac{1\downarrow}{2s}\frac{1\downarrow1\downarrow1\downarrow}{2p}\frac{1\downarrow}{3s}$

Step7: Determine electrons of Phosphorus

Phosphorus has atomic number 15, so 15 electrons. $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$

Step8: Draw orbital diagram for Phosphorus

$\frac{1\downarrow}{1s}\frac{1\downarrow}{2s}\frac{1\downarrow1\downarrow1\downarrow}{2p}\frac{1\downarrow}{3s}\frac{1}{3p}\frac{1}{3p}\frac{1}{3p}$

Answer:

Element	# e-	Full e- configuration	Orbital diagram
Lithium	3 e-	$1s^{2}2s^{1}$	$\frac{1\downarrow}{1s}\frac{1}{2s}$
Aluminum	13 e-	$1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$	$\frac{1\downarrow}{1s}\frac{1\downarrow}{2s}\frac{1\downarrow1\downarrow1\downarrow}{2p}\frac{1\downarrow}{3s}\frac{1}{3p}$
Magnesium	12 e-	$1s^{2}2s^{2}2p^{6}3s^{2}$	$\frac{1\downarrow}{1s}\frac{1\downarrow}{2s}\frac{1\downarrow1\downarrow1\downarrow}{2p}\frac{1\downarrow}{3s}$
Phosphorus	15 e-	$1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$	$\frac{1\downarrow}{1s}\frac{1\downarrow}{2s}\frac{1\downarrow1\downarrow1\downarrow}{2p}\frac{1\downarrow}{3s}\frac{1}{3p}\frac{1}{3p}\frac{1}{3p}$