question 10 of 10\n2 (nh₄)₃po₄\nammonium phosphate\nhow many total atoms are in 2 (nh₄)₃po₄?\n32\n12\n64\n40\…
question 10 of 10\n2 (nh₄)₃po₄\nammonium phosphate\nhow many total atoms are in 2 (nh₄)₃po₄?\n32\n12\n64\n40\n16
Answer
Explanation:
Step1: Analyze atoms in one $(NH_4)_3PO_4$
In $(NH_4)_3PO_4$, for nitrogen (N): there are 3 N atoms (since there is a sub - script 3 outside the ammonium ion), for hydrogen (H): $4\times3 = 12$ H atoms, for phosphorus (P): 1 P atom, and for oxygen (O): 4 O atoms. So in one $(NH_4)_3PO_4$ molecule, the total number of atoms is $3 + 12+1 + 4=20$ atoms.
Step2: Calculate atoms in 2 $(NH_4)_3PO_4$
Since we have 2 formula units of $(NH_4)_3PO_4$, we multiply the number of atoms in one unit by 2. So the total number of atoms is $20\times2 = 40$ atoms.
Answer:
40