question 1 of 10\nhow many atoms does 32 g of sulfur contain?\na. 6.02×10²³\nb. $\frac{6.02×10^{23}}{32}$\nc…

question 1 of 10\nhow many atoms does 32 g of sulfur contain?\na. 6.02×10²³\nb. $\frac{6.02×10^{23}}{32}$\nc. 32×(6.02×10²³)\nd. $\frac{6.02×10^{23}}{16}$

question 1 of 10\nhow many atoms does 32 g of sulfur contain?\na. 6.02×10²³\nb. $\frac{6.02×10^{23}}{32}$\nc. 32×(6.02×10²³)\nd. $\frac{6.02×10^{23}}{16}$

Answer

Explanation:

Step1: Determine molar mass of sulfur

The molar mass of sulfur (S) is 32 g/mol.

Step2: Use Avogadro's number

1 mole of any substance contains $6.02\times 10^{23}$ atoms. Since we have 32 g of sulfur which is 1 mole (because mass = 32 g and molar - mass = 32 g/mol), the number of atoms is $6.02\times 10^{23}$.

Answer:

A. $6.02\times 10^{23}$