question 12 (1 point) which of the following chemical reactions does not fit the law of conservation of…

Explanation:

Step1: Recall law of conservation of matter

The law of conservation of matter states that in a chemical reaction, the total mass of the reactants must equal the total mass of the products, which means the number of atoms of each element must be the same on both sides of the chemical equation.

Step2: Analyze option a

For the reaction $6CO_2 + 6H_2O\rightarrow C_6H_{12}O_6+6O_2$, on the left - hand side, we have 6 carbon atoms ($6\times1$ in $CO_2$), 12 hydrogen atoms ($6\times2$ in $H_2O$) and 18 oxygen atoms ($6\times2$ in $CO_2$ and $6\times1$ in $H_2O$). On the right - hand side, we have 6 carbon atoms in $C_6H_{12}O_6$, 12 hydrogen atoms in $C_6H_{12}O_6$ and 18 oxygen atoms ($6$ in $C_6H_{12}O_6$ and $6\times2$ in $O_2$). It follows the law.

Step3: Analyze option b

For the reaction $C_6H_{12}O_6 + O_2\rightarrow CO_2+H_2O$, if we count the atoms without balancing the equation, on the left - hand side we have 6 carbon atoms in $C_6H_{12}O_6$, 12 hydrogen atoms in $C_6H_{12}O_6$ and some oxygen atoms in $C_6H_{12}O_6$ and $O_2$. If we try to balance it: $C_6H_{12}O_6 + 6O_2\rightarrow6CO_2 + 6H_2O$ is the balanced form. The given unbalanced form does not follow the law of conservation of matter as written.

Step4: Analyze option c

For the reaction $C_6H_{12}O_6+6O_2\rightarrow6CO_2 + 6H_2O$, on the left - hand side, we have 6 carbon atoms in $C_6H_{12}O_6$, 12 hydrogen atoms in $C_6H_{12}O_6$ and 18 oxygen atoms ($6$ in $C_6H_{12}O_6$ and $6\times2$ in $O_2$). On the right - hand side, we have 6 carbon atoms ($6\times1$ in $CO_2$), 12 hydrogen atoms ($6\times2$ in $H_2O$) and 18 oxygen atoms ($6\times2$ in $CO_2$ and $6\times1$ in $H_2O$). It follows the law.

Answer:

B. $C_6H_{12}O_6 + O_2\rightarrow CO_2+H_2O$