question 13\nthe molar mass of c₂h₄(nh₂)₃ is blank 1 g/mol.\nblank 1 add your answer\n\nquestion 14\nif a…

question 13\nthe molar mass of c₂h₄(nh₂)₃ is blank 1 g/mol.\nblank 1 add your answer\n\nquestion 14\nif a box of cacl₂ has a mass of 2.56 g. blank 1 moles are in the box. blank 2x10^blank 3 atoms are in the box.\nblank 1 add your answer\nblank 2 add your answer\nblank 3 add your answer\n\nquestion 15\nlast saved 8:45:33 pm\nquestions filter (20)

question 13\nthe molar mass of c₂h₄(nh₂)₃ is blank 1 g/mol.\nblank 1 add your answer\n\nquestion 14\nif a box of cacl₂ has a mass of 2.56 g. blank 1 moles are in the box. blank 2x10^blank 3 atoms are in the box.\nblank 1 add your answer\nblank 2 add your answer\nblank 3 add your answer\n\nquestion 15\nlast saved 8:45:33 pm\nquestions filter (20)

Answer

Explanation:

Step1: Calculate molar mass of (C_2H_4(NH_2)_3)

The molar - mass of carbon ((C)) is approximately (12.01\ g/mol), hydrogen ((H)) is approximately (1.01\ g/mol), and nitrogen ((N)) is approximately (14.01\ g/mol). In (C_2H_4(NH_2)_3), there are (2) carbon atoms, ((4 + 2\times3)=10) hydrogen atoms, and (3) nitrogen atoms. The molar mass (M) is (M = 2\times12.01+10\times1.01 + 3\times14.01) [ \begin{align*} M&=24.02+10.1+42.03\ &=76.15\ g/mol \end{align*} ]

Step2: Calculate moles of (CaCl_2)

The molar mass of (CaCl_2): The molar - mass of calcium ((Ca)) is approximately (40.08\ g/mol), and the molar - mass of chlorine ((Cl)) is approximately (35.45\ g/mol). The molar mass of (CaCl_2) is (M_{CaCl_2}=40.08 + 2\times35.45=40.08+70.9 = 110.98\ g/mol). The number of moles (n) of (CaCl_2) with a mass (m = 2.56\ g) is (n=\frac{m}{M_{CaCl_2}}=\frac{2.56}{110.98}\approx0.0231) moles.

Step3: Calculate number of atoms in (CaCl_2)

In one formula - unit of (CaCl_2), there are (3) atoms ((1) (Ca) and (2) (Cl)). The number of formula - units of (CaCl_2) is (N_{f}=n\times N_A), where (N_A = 6.022\times10^{23}\ mol^{-1}). (N_{f}=0.0231\times6.022\times10^{23}\approx1.391\times10^{22}) formula - units. The number of atoms (N) is (N = 3\times N_{f}=3\times1.391\times10^{22}=4.173\times10^{22}) atoms, which can be written as (4.17\times10^{22}) (rounded to two decimal places).

Answer:

Blank 1 (for (C_2H_4(NH_2)_3) molar mass): (76.15) Blank 1 (for (CaCl_2) moles): (0.0231) Blank 2 (for (CaCl_2) atoms coefficient): (4.17) Blank 3 (for (CaCl_2) atoms exponent): (22)