question 16 of 20 identify the precipitate that forms and the spectator ions that remain in the solution…
question 16 of 20 identify the precipitate that forms and the spectator ions that remain in the solution following this reaction. answer bank bas(s) so₄²⁻(aq) k⁺(aq) kno₃(s) s²⁻(aq) bai₂(s) ba²⁺(aq) no₃⁻(aq) i⁻(aq) baso₄(s)
Answer
Explanation:
Step1: Recall solubility rules
Most sulfates are soluble except those of barium ($Ba^{2 + }$), lead ($Pb^{2+}$), calcium ($Ca^{2+}$) etc. Barium sulfate ($BaSO_{4}$) is insoluble and will form a precipitate. Spectator ions are those that do not participate in the actual chemical reaction and remain in solution.
Step2: Identify spectator ions
Potassium ($K^{+}$) and nitrate ($NO_{3}^{-}$) are common spectator - ions in many reactions as their salts are generally soluble.
Answer:
Precipitate: $BaSO_{4}(s)$ Spectator ions: $K^{+}(aq), NO_{3}^{-}(aq)$