question 17 using the equation 2c6h6 + 15o2 → 12co2+ 22h2o, blank 1 grams of co2 would be produced from 3.6…

question 17 using the equation 2c6h6 + 15o2 → 12co2+ 22h2o, blank 1 grams of co2 would be produced from 3.6 moles of c6h6. blank 1 add your answer 3 points

question 17 using the equation 2c6h6 + 15o2 → 12co2+ 22h2o, blank 1 grams of co2 would be produced from 3.6 moles of c6h6. blank 1 add your answer 3 points

Answer

Explanation:

Step1: Determine mole - ratio

From the balanced equation (2C_{12}H_{22}+15O_2\rightarrow12CO_2 + 22H_2O), the mole - ratio of (C_{12}H_{22}) to (CO_2) is (2:12) or (1:6).

Step2: Calculate moles of (CO_2)

If we have 9.6 moles of (C_{12}H_{22}), using the mole - ratio, the moles of (CO_2) produced is (n(CO_2)=9.6\times6 = 57.6) moles.

Step3: Calculate mass of (CO_2)

The molar mass of (CO_2) is (M(CO_2)=12 + 2\times16=44) g/mol. The mass of (CO_2), (m = n\times M), so (m(CO_2)=57.6\times44 = 2534.4) g.

Answer:

2534.4