question 27 of 29 determine the quantity of atoms of vanadium in 1.28 grams of vanadium

Explanation:

Step1: Find molar mass of vanadium

The molar mass of vanadium (V) is approximately 50.94 g/mol.

Step2: Calculate moles of vanadium

Use the formula $n=\frac{m}{M}$, where $m = 1.28$ g and $M=50.94$ g/mol. So $n=\frac{1.28}{50.94}\approx0.0251$ mol.

Step3: Calculate number of atoms

Use Avogadro's number $N_A = 6.022\times10^{23}$ atoms/mol. The number of atoms $N=n\times N_A$. So $N = 0.0251\times6.022\times10^{23}\approx1.51\times 10^{22}$ atoms.

Answer:

$1.51\times 10^{22}$ atoms