this question builds on your problem - solving from the previous question. a solution of hydrochloric acid…

this question builds on your problem - solving from the previous question. a solution of hydrochloric acid has a molarity of 2.25 m hcl. if a reaction requires 5.80 g of hcl, what volume of solution should be used? use the number of moles you calculated in the previous question: 0.159 mol hcl.

this question builds on your problem - solving from the previous question. a solution of hydrochloric acid has a molarity of 2.25 m hcl. if a reaction requires 5.80 g of hcl, what volume of solution should be used? use the number of moles you calculated in the previous question: 0.159 mol hcl.

Answer

Explanation:

Step1: Recall molarity formula

The formula for molarity $M=\frac{n}{V}$, where $M$ is molarity, $n$ is the number of moles, and $V$ is the volume in liters. We need to solve for $V$, so $V = \frac{n}{M}$.

Step2: Substitute given values

We are given that $n = 0.159$ mol and $M=2.25$ M. Substituting into the formula $V=\frac{0.159\text{ mol}}{2.25\text{ mol/L}}$.

Step3: Calculate the volume

$V=\frac{0.159}{2.25}\text{ L}\approx0.0707$ L. Since $1\text{ L} = 1000\text{ mL}$, $V = 0.0707\times1000\text{ mL}=70.7$ mL.

Answer:

$70.7$ mL