question 4\nfor a first order reaction, if we graph lna vs. t, we get a straight line with a slope equal…
question 4\nfor a first order reaction, if we graph lna vs. t, we get a straight line with a slope equal to\nk\n - k\ninitial concentration\nrate
Answer
Brief Explanations:
The integrated rate - law for a first - order reaction is $\ln[A]=\ln[A]_0 - kt$. This is in the form of a straight - line equation $y = mx + b$ where $y=\ln[A]$, $x = t$, $b=\ln[A]_0$ (the y - intercept), and the slope $m=-k$.
Answer:
-k