question: how many grams of caco3 are there in 3.5 mole caco3? 1molecaco3 = 100.09gcaco3 solving strategy…

question: how many grams of caco3 are there in 3.5 mole caco3? 1molecaco3 = 100.09gcaco3 solving strategy: given × conversion factor 1 × conversion factor 2... = calculated answer enter the answers in the boxes to show your work and solve the problem.

question: how many grams of caco3 are there in 3.5 mole caco3? 1molecaco3 = 100.09gcaco3 solving strategy: given × conversion factor 1 × conversion factor 2... = calculated answer enter the answers in the boxes to show your work and solve the problem.

Answer

Explanation:

Step1: Identify given and conversion factor

Given is 3.5 moles of $CaCO_3$, conversion factor is 100.09 g per 1 mole of $CaCO_3$. $3.5\ mol\times\frac{100.09\ g}{1\ mol}$

Step2: Perform multiplication

$3.5\times100.09 = 350.315$

Answer:

350.315 g