question 4 (1 point)\nassign oxidation numbers to agno₃.\nag - \nn - \no -

Answer

Explanation:

Step1: Recall oxidation - number rules

Oxidation number of oxygen is usually - 2 and for a neutral compound, the sum of oxidation numbers of all atoms is 0.

Step2: Find oxidation number of O

Oxygen has an oxidation number of - 2 in most compounds. In $AgNO_3$, there are 3 oxygen atoms, so the total contribution from oxygen is $3\times(- 2)=-6$.

Step3: Find oxidation number of Ag

Silver (Ag) is a monovalent metal in this compound and has an oxidation number of + 1.

Step4: Calculate oxidation number of N

Let the oxidation number of N be $x$. Since the sum of oxidation numbers in $AgNO_3$ is 0, we have $(+1)+x+(-6) = 0$. Solving for $x$ gives $x=+5$.

Answer:

Ag - +1, N - +5, O - -2