question 6 (1 point)\nassign oxidation numbers to ch₃oh.\nc - h - o -

Answer

Explanation:

Step1: Set rules for oxidation numbers

Hydrogen usually has an oxidation number of +1 in compounds, and oxygen usually has an oxidation number of -2 in compounds. Let the oxidation number of carbon in (CH_{3}OH) be (x).

Step2: Calculate oxidation number of carbon

The sum of oxidation numbers in a neutral compound is zero. In (CH_{3}OH), there is 1 carbon atom, 4 hydrogen atoms and 1 oxygen atom. So we have the equation (x+(+ 1)\times4+(-2)=0). Solving for (x): (x + 4-2=0), (x=-2).

Step3: Determine oxidation number of hydrogen

Hydrogen has an oxidation number of +1 as per the common - rule for non - metal hydrides.

Step4: Determine oxidation number of oxygen

Oxygen has an oxidation number of -2 as per the common - rule for compounds other than peroxides.

Answer:

C -2, H +1, O -2