question 3 (1 point)\nwhat is the molarity of a naoh solution with 4.55 x 10^(-3) moles in 25.00 ml?\na)…

question 3 (1 point)\nwhat is the molarity of a naoh solution with 4.55 x 10^(-3) moles in 25.00 ml?\na) 0.182 g/l\nb) 1.82 x 10^(-4) mol/l\nc) 0.182 mol/l\nd) 1.82 x 10^(-4) g/l

question 3 (1 point)\nwhat is the molarity of a naoh solution with 4.55 x 10^(-3) moles in 25.00 ml?\na) 0.182 g/l\nb) 1.82 x 10^(-4) mol/l\nc) 0.182 mol/l\nd) 1.82 x 10^(-4) g/l

Answer

Explanation:

Step1: Convert volume to liters

The volume is given as 25.00 mL. Since 1 L = 1000 mL, we convert it to liters: $V=25.00\ mL\times\frac{1\ L}{1000\ mL}=0.025\ L$.

Step2: Use the molarity formula

The molarity formula is $M = \frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume in liters. Given $n = 4.55\times10^{-3}$ moles and $V=0.025\ L$, we substitute the values: $M=\frac{4.55\times 10^{-3}\ mol}{0.025\ L}=0.182\ mol/L$.

Answer:

C. 0.182 mol/L