question 5 (2 points)\nwhat is the net ionic equation for the reaction of sodium carbonate with iron (ii)…

question 5 (2 points)\nwhat is the net ionic equation for the reaction of sodium carbonate with iron (ii) nitrate?\nfe²⁺ (aq) + co₃²⁻ (aq) → feco₃ (s)\nna⁺ (aq) + no₃⁻ (aq) → nano₃ (s)\nfe³⁺ (aq) + 3co₃⁻ (aq) → fe(co₃)₃ (s)\nfe²⁺ (aq) + 2co₃⁻ (aq) → fe(co₃)₂ (s)
Answer
Explanation:
Step1: Write the balanced molecular equation
Sodium carbonate ($Na_2CO_3$) reacts with iron (II) nitrate ($Fe(NO_3)_2$) to form sodium nitrate ($NaNO_3$) and iron (II) carbonate ($FeCO_3$). The molecular equation is $Na_2CO_3(aq)+Fe(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+FeCO_3(s)$.
Step2: Write the complete ionic equation
Break all aqueous - soluble compounds into ions. $2Na^+(aq)+CO_3^{2 - }(aq)+Fe^{2+}(aq)+2NO_3^-(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+FeCO_3(s)$.
Step3: Write the net ionic equation
Cancel out the spectator ions ($Na^+$ and $NO_3^-$). The net ionic equation is $Fe^{2+}(aq)+CO_3^{2 - }(aq)\rightarrow FeCO_3(s)$.
Answer:
$Fe^{2+}(aq)+CO_3^{2 - }(aq)\rightarrow FeCO_3(s)$