question 9 1 pts a marble has a density of 2.87 g/cm³ and mass of 66g, what is the volume of the marble…

question 9 1 pts a marble has a density of 2.87 g/cm³ and mass of 66g, what is the volume of the marble? round the answer to the correct number of significant figures. question 10 1 pts a student calculated the density of a metal bar to be 4.7 g/cm³, the actual density of the metal bar is 3.5 g/cm³. what is the percent error of the students calculation? round the answer to the correct significant figures. type the numerical value only.

question 9 1 pts a marble has a density of 2.87 g/cm³ and mass of 66g, what is the volume of the marble? round the answer to the correct number of significant figures. question 10 1 pts a student calculated the density of a metal bar to be 4.7 g/cm³, the actual density of the metal bar is 3.5 g/cm³. what is the percent error of the students calculation? round the answer to the correct significant figures. type the numerical value only.

Answer

Explanation:

Step1: Recall density formula

The density formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass and $V$ is volume. We can re - arrange it to solve for volume $V = \frac{m}{\rho}$.

Step2: Substitute values for marble

Given $m = 66g$ and $\rho=2.87g/cm^{3}$, then $V=\frac{66}{2.87}\ cm^{3}\approx23cm^{3}$ (rounded to two significant figures as 66 has two significant figures).

Step3: Recall percent - error formula

The percent - error formula is $\text{Percent Error}=\left|\frac{\text{Experimental Value}-\text{True Value}}{\text{True Value}}\right|\times100%$.

Step4: Substitute values for metal bar

The experimental value of density is $\rho_{exp}=4.7g/cm^{3}$ and the true value is $\rho_{true}=3.5g/cm^{3}$. Then $\text{Percent Error}=\left|\frac{4.7 - 3.5}{3.5}\right|\times100%=\left|\frac{1.2}{3.5}\right|\times100%\approx34%$ (rounded to two significant figures as 4.7 and 3.5 have two significant figures).

Answer:

Question 9: 23 Question 10: 34