questions\nuse the following information to answer the next two questions.\nin this written response…

questions\nuse the following information to answer the next two questions.\nin this written response question, include all of your units, formulas (if used), calculations and work for full marks. record your answer to the correct number of significant digits.\n2. a chemistry 20 student conducted an experiment in order to identify a pure gas sample. this is the data collected. calculate the molar mass of the gas\nmass of gas container before 29.9785 g\nmass of gas container after 29.3265 g\npressure of the gas 92.00 kpa\nvolume of the container with gas 825.5 ml\ntemperature of the gas 21.90°c\nyour answer:\n3. what is the possible identity of the gas?\nyour answer:

questions\nuse the following information to answer the next two questions.\nin this written response question, include all of your units, formulas (if used), calculations and work for full marks. record your answer to the correct number of significant digits.\n2. a chemistry 20 student conducted an experiment in order to identify a pure gas sample. this is the data collected. calculate the molar mass of the gas\nmass of gas container before 29.9785 g\nmass of gas container after 29.3265 g\npressure of the gas 92.00 kpa\nvolume of the container with gas 825.5 ml\ntemperature of the gas 21.90°c\nyour answer:\n3. what is the possible identity of the gas?\nyour answer:

Answer

Explanation:

Step1: Calculate mass of the gas

Mass of gas = Mass before - Mass after $m = 29.9785\ g - 29.3265\ g= 0.6520\ g$

Step2: Convert units

Convert volume to liters: $V = 825.5\ mL=0.8255\ L$ Convert temperature to Kelvin: $T=(21.90 + 273.15)\ K = 295.05\ K$ Convert pressure to atmospheres: $P = 92.00\ kPa\times\frac{1\ atm}{101.325\ kPa}\approx0.908\ atm$

Step3: Use the ideal - gas law ($PV = nRT$) to find the number of moles ($n$)

$n=\frac{PV}{RT}$, where $R = 0.0821\ L\cdot atm/(mol\cdot K)$ $n=\frac{0.908\ atm\times0.8255\ L}{0.0821\ L\cdot atm/(mol\cdot K)\times295.05\ K}\approx0.0309\ mol$

Step4: Calculate the molar mass ($M$)

$M=\frac{m}{n}$ $M=\frac{0.6520\ g}{0.0309\ mol}\approx21.1\ g/mol$

Answer:

The molar mass of the gas is approximately $21.1\ g/mol$