quiz - gas laws\nname: ebtasam\nquestions\nuse the following information to answer the next question.\nthe…

quiz - gas laws\nname: ebtasam\nquestions\nuse the following information to answer the next question.\nthe unbalanced reaction equation for the combustion of propane gas is given as follows:\n____c₃h₈(g) + ____o₂(g) → ____co₂(g) + ____h₂o(g)\n8. if 27l of propane gas is burned with excess oxygen, the expected volume of carbon dioxide produced will be ____ l.\nyour answer: \n

quiz - gas laws\nname: ebtasam\nquestions\nuse the following information to answer the next question.\nthe unbalanced reaction equation for the combustion of propane gas is given as follows:\n____c₃h₈(g) + ____o₂(g) → ____co₂(g) + ____h₂o(g)\n8. if 27l of propane gas is burned with excess oxygen, the expected volume of carbon dioxide produced will be ____ l.\nyour answer: \n

Answer

Explanation:

Step1: Balance the chemical equation

$C_3H_8(g)+5O_2(g)\rightarrow3CO_2(g) + 4H_2O(g)$

Step2: Use Avogadro's law

At the same temperature and pressure, the volume - ratio of gases is equal to the mole - ratio. The mole - ratio of $C_3H_8$ to $CO_2$ is $1:3$. So if $V_{C_3H_8}=27L$, then $V_{CO_2}=3\times V_{C_3H_8}$.

Step3: Calculate the volume of $CO_2$

$V_{CO_2}=3\times27L = 81L$

Answer:

81