what is the ratio of al³⁺ ions to s²⁻ ions in a neutral compound?\no 1:1\no 2:1\no 2:3\no 3:2

Explanation:

Step1: Determine charge balance

For a neutral compound, the total positive charge must equal the total negative charge. Aluminum ion ($Al^{3 + }$) has a charge of + 3 and sulfide ion ($S^{2 - }$) has a charge of - 2.

Step2: Find least - common multiple

The least - common multiple of 3 and 2 is 6.

Step3: Calculate ion ratio

To get a total positive charge of + 6, we need 2 $Al^{3+}$ ions ($2\times3 = 6$). To get a total negative charge of - 6, we need 3 $S^{2 - }$ ions ($3\times2=6$). So the ratio of $Al^{3+}$ ions to $S^{2 - }$ ions is 2:3.

Answer:

C. 2:3