what is the ratio of sr²⁺ ions to br⁻ ions in a neutral compound?\n1:1\n1:2\n2:1\n3:2

what is the ratio of sr²⁺ ions to br⁻ ions in a neutral compound?\n1:1\n1:2\n2:1\n3:2
Answer
Explanation:
Step1: Determine ion charges
Strontium ($Sr^{2 + }$) has a +2 charge and bromide ($Br^{-}$) has a - 1 charge.
Step2: Balance charges
To form a neutral compound, the total positive charge must equal the total negative charge. Let the number of $Sr^{2+}$ ions be $x$ and the number of $Br^{-}$ ions be $y$. We need $2x=y$. So, if $x = 1$, then $y=2$.
Answer:
B. 1:2