which reaction is endothermic?\nhcl + naoh → nacl + h₂o + 58 kj\n6co₂ + 12h₂o + energy → c₆h₁₂o₆ + 6o₂ +…

Explanation:

Step1: Understand endothermic reactions

Endothermic reactions absorb energy. In chemical - equations, if energy is on the reactant side, the reaction is endothermic. If energy is on the product side, the reaction is exothermic.

Step2: Analyze each option

• For $\mathrm{HCl}+\mathrm{NaOH}\rightarrow\mathrm{NaCl}+\mathrm{H}_2\mathrm{O}+58\mathrm{\ kJ}$, energy is on the product side, so it is exothermic.
• For $6\mathrm{CO}_2 + 12\mathrm{H}_2\mathrm{O}+\text{energy}\rightarrow\mathrm{C}6\mathrm{H}{12}\mathrm{O}_6+6\mathrm{O}_2 + 6\mathrm{H}_2\mathrm{O}$, energy is on the reactant side, so it is endothermic.
• For $2\mathrm{Na}+\mathrm{Cl}_2\rightarrow2\mathrm{NaCl}+\text{energy}$, energy is on the product side, so it is exothermic.
• For $2\mathrm{C}_2\mathrm{H}_6+7\mathrm{O}_2\rightarrow4\mathrm{CO}_2 + 6\mathrm{H}_2\mathrm{O}+2502\mathrm{\ kJ}$, energy is on the product side, so it is exothermic.

Answer:

$6\mathrm{CO}_2 + 12\mathrm{H}_2\mathrm{O}+\text{energy}\rightarrow\mathrm{C}6\mathrm{H}{12}\mathrm{O}_6+6\mathrm{O}_2 + 6\mathrm{H}_2\mathrm{O}$