the reaction below shows how silver chloride can be synthesized.\nagno₃ + nacl → nano₃ + agcl\nhow many…

the reaction below shows how silver chloride can be synthesized.\nagno₃ + nacl → nano₃ + agcl\nhow many moles of silver chloride are produced from 15.0 mol of silver nitrate?\n1.0 mol\n15.0 mol\n30.0 mol\n45.0 mol

the reaction below shows how silver chloride can be synthesized.\nagno₃ + nacl → nano₃ + agcl\nhow many moles of silver chloride are produced from 15.0 mol of silver nitrate?\n1.0 mol\n15.0 mol\n30.0 mol\n45.0 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced chemical equation $AgNO_3+NaCl\rightarrow NaNO_3 + AgCl$, the mole - ratio of $AgNO_3$ to $AgCl$ is 1:1.

Step2: Calculate moles of $AgCl$

If the number of moles of $AgNO_3$ is $n_{AgNO_3}=15.0$ mol, and since $\frac{n_{AgCl}}{n_{AgNO_3}} = 1$, then $n_{AgCl}=n_{AgNO_3}=15.0$ mol.

Answer:

B. 15.0 mol