the reaction of zinc (ii) hydroxide with phosphoric acid produces zinc (ii) phosphate and water. balance the…

the reaction of zinc (ii) hydroxide with phosphoric acid produces zinc (ii) phosphate and water. balance the reaction by completing the chemical equation with the molar coefficients. zn(oh)₂ + h₃po₄ → zn₃(po₄)₂ + h₂o 2 3 4 5 6

the reaction of zinc (ii) hydroxide with phosphoric acid produces zinc (ii) phosphate and water. balance the reaction by completing the chemical equation with the molar coefficients. zn(oh)₂ + h₃po₄ → zn₃(po₄)₂ + h₂o 2 3 4 5 6

Answer

Explanation:

Step1: Balance zinc atoms

We have 3 zinc atoms in $Zn_3(PO_4)_2$, so we put a 3 in front of $Zn(OH)_2$: $3Zn(OH)_2 + H_3PO_4\rightarrow Zn_3(PO_4)_2 + H_2O$.

Step2: Balance phosphate groups

There are 2 phosphate groups in $Zn_3(PO_4)_2$, so we put a 2 in front of $H_3PO_4$: $3Zn(OH)_2+2H_3PO_4\rightarrow Zn_3(PO_4)_2 + H_2O$.

Step3: Balance hydrogen and oxygen atoms

On the left - hand side, we have $3\times2 + 2\times3=12$ hydrogen atoms and $3\times2+2\times4 = 14$ oxygen atoms. On the right - hand side, in $Zn_3(PO_4)_2$ we have 8 oxygen atoms. So we need 6 water molecules to balance hydrogen and oxygen. The balanced equation is $3Zn(OH)_2 + 2H_3PO_4\rightarrow Zn_3(PO_4)_2+6H_2O$.

Answer:

$3Zn(OH)_2 + 2H_3PO_4\rightarrow Zn_3(PO_4)_2+6H_2O$