reduce the following equation to a net ionic equation: 2na⁺ + so₄²⁻ + ba²⁺ + 2cl⁻ → 2na⁺ + 2cl⁻ +…

reduce the following equation to a net ionic equation: 2na⁺ + so₄²⁻ + ba²⁺ + 2cl⁻ → 2na⁺ + 2cl⁻ + baso₄\n2na⁺ + 2cl⁻ → 2nacl\nso₄²⁻ + ba²⁺ → baso₄\n2na⁺ + so₄²⁻ → na₂so₄

reduce the following equation to a net ionic equation: 2na⁺ + so₄²⁻ + ba²⁺ + 2cl⁻ → 2na⁺ + 2cl⁻ + baso₄\n2na⁺ + 2cl⁻ → 2nacl\nso₄²⁻ + ba²⁺ → baso₄\n2na⁺ + so₄²⁻ → na₂so₄

Answer

Explanation:

Step1: Identify spectator ions

Spectator ions are those that appear on both sides of the ionic - equation unchanged. Here, $2Na^{+}$ and $2Cl^{-}$ are spectator ions.

Step2: Remove spectator ions

Remove $2Na^{+}$ and $2Cl^{-}$ from both sides of the given ionic equation $2Na^{+}+SO_{4}^{2 -}+Ba^{2 +}+2Cl^{-}\to2Na^{+}+2Cl^{-}+BaSO_{4}$.

Answer:

$SO_{4}^{2 -}+Ba^{2 +}\to BaSO_{4}$