review the equation below.\n2kclo₃ → 2kcl + 3o₂\nhow many moles of oxygen are produced when 2 mol of…

review the equation below.\n2kclo₃ → 2kcl + 3o₂\nhow many moles of oxygen are produced when 2 mol of potassium chlorate (kclo₃) decompose?\n1\n2\n3\n6
Answer
Explanation:
Step1: Analyze the mole - ratio
From the balanced chemical equation $2KClO_3\rightarrow2KCl + 3O_2$, the mole - ratio of $KClO_3$ to $O_2$ is $2:3$.
Step2: Calculate moles of oxygen
Given 2 moles of $KClO_3$. Let the moles of $O_2$ be $x$. Using the mole - ratio $\frac{n_{KClO_3}}{n_{O_2}}=\frac{2}{3}$. Substituting $n_{KClO_3} = 2$ mol, we get $\frac{2}{x}=\frac{2}{3}$. Cross - multiplying gives $2x=2\times3$, so $x = 3$ mol.
Answer:
C. 3